Mark M. answered 02/06/24
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫ tanxcosxdx = ∫ (sinx/cosx)cosxdx = ∫sinxdx = -cosx + C
Alicia F.
asked 02/06/24Mark M. answered 02/06/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫ tanxcosxdx = ∫ (sinx/cosx)cosxdx = ∫sinxdx = -cosx + C
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