Mark M. answered 02/05/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
z = f(x,y) = √(9 - x2 - y2)
z2 = 9 - x2 - y2
So, x2 + y2 + z2 = 9 (Graph is the sphere of radius 3 with center (0,0,0))
z = f(x,y) = √(9 - x2 - y2) is the upper hemisphere with radius 3 and center (0,0,0).
Domain = {(x,y) l -3 ≤ x ≤3 and -3 ≤ y ≤ 3}
Range = {z l 0 ≤ z ≤ 3}
For c = 3, the level curve f(x,y) = 3 is the point (0,0,3)
For c = 0, 1, and 2, the level curves are circles with centers on the z-axis parallel to the xy-plane.
D G.
Also, this is a function x,y so isn't domain -3<=x<=3 and range -3<=y<=3?02/05/24