Raymond B. answered 01/31/24
Math, microeconomics or criminal justice
a) f'(x) = 2x-2
b) g'(x) = 12x^3 - 3
c) h'(t) =((2t^3 +5t)(6t) - (3t^2-9)(6t^2+5))/(2t^3+5t)^2 -3/t^2 mostly the quotient rule, then expand, simplify
= (12t^4 -30t^2 - 18t^4 -15t^2 +54t^2 +45)/(4t^6 +20t^4 +25t^2) - 3/t^2
= (-6t^4 +9t^2 +45)/(4t^6+20t^4 +25t^2) - 3/t^2
unless you meant
h(x)=3t^2 -9/t^3 +5t +3/t
then
h'(t)= 6t +27/t^4 +5 -3/t^2