The current is flowing at 1/4 the boat's speed. Here are the calculations:
(B+C)36 = (B-C)60
36B + 36C = 60B - 60C
96C = 24B
B = 4C
So, B+C = B + (B/4) = 1.25B
Distance/(1.25B) = 36 minutes.
If we multiply by 1.25, we get
D/B=1.25*36 = 45 minutes, and this is the time it would take to go the same distance without any current.
We could also do this:
B-C = B-(B/4) = 0.75B
Distance/(0.75B) = 60 minutes
Multiply both sides by 0.75 and we get
D/B = 0.75*60 = 45 minutes,
and that is a good check on our answer.
We still don't know either the distance, the speed of the boat, nor the speed of the current. But when we can reduce the speeds to multiples of one variable, we can use that to find the time needed to traverse the same distance without the current.