a rock is dropped from a high building. The acceleration due to gravity is -10m/s^2. Find the distance travelled by this rock from t=2s to t=4s

Answer 1

a =-10m/sec^2 = effect of gravity

from t=2 to t= 4 seconds

a rock dropped will travel

h(4)-h(2)= -(10/2)(4^2) - (10/2)(2^2)= -80+20= -60

|-60| = 60 meters down from its initial position

Answer 2

To calculate the distance traveled you would use the absolute magnitude of the displacement during these two times, d = |x₂ - x₁|, where x₁ = x₀ + v₀ t + 1/2 a t₁², and x₂ = x₀ + v₀ t₂ + 1/2 a t₂². Note, that the answer does not depend on x₀, as it will cancel out. Also, v₀ = 0 m/s because the rock starts from rest. Let me know if you have any further questions. You may schedule short sessions as well.