The relationship between displacement s and velocity v is given by (1/3)s^2 -4v^2 =12 find the acceleration (a) at any time.

Question

Rate of change question.

Answer 1

(1/3)s² - 4v² = 12

(2/3)s(ds/dt) - 8v(dv/dt) = 0

Since ds/dt = v and dv/dt = acceleration = a, we have (2/3)sv - 8va = 0

So, 8va = (2/3)sv

a = (1/12)s