I'm not to sure but it deals with f o g

Question

Let ƒ (x) = 5 - [sqrt]x^2+1 and g(x) =x - 4.

Then (ƒ ∘ g)(6)=    

,

(ƒ ∘ g)(x)=

Answer 1

f(x) = 5 - √(x²+1) and g(x) = x - 4

g(6) = 6 - 4 = 2

So, (f o g)(6) = f(g(6)) = f(2) = 5 - √(2²+1) = 5 - √5