Sin, Cos, Tan, Sec

Question

if sin(θ) = 8/10, 0 ≤ θ ≤ pi/2, then

cos(θ) =

tan(θ) =

sec(θ) =

Answer 1

cosT = 3/5

tanT=4/3

secT= 5/3

if sinT=8/10=4/5 and 0/=<T</=pi/2=90 degrees, T is in quadrant I, where all trig functions > 0, (except when T=0 or pi/2, which doesn't apply to this problem)

sinT = opposite/hypotenuse = 4/5

cosT = adjacent/hypotenuse = 3/5 as adjacent side = sqr(5^2 - 4^2) = 3

tanT = opposite/adjacent = 4/3

secT = 1/cosT = 1/3/5 = 5/3