Mark M. answered 01/04/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Since f is decreasing, the minimum value of f on each subinterval occurs at the right endpoint of the subinterval and the maximum value of f on each subinterval occurs at the left endpoint.
lower sum = f(2)(2-0) + f(4)(4-2) + f(6)(6-4) + f(8)(8-6) + f(10)(10-8)
= 2(21 + 9 + (-4) + (-18) + (-37)) = -58
upper sum = f(0)(2-0) + f(2)(4-2) + f(4)(6-4) + f(6)(8-6) + f(8)(10-8)
= 2(32 + 21 + 9 + (-4) + (-18)) = 80
So, -58 ≤ ∫(0 to 10) f(x)dx ≤ 80