Mark M. answered 12/15/23
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
y = 3ax + sin(bx)
y' = (ln3)3ax(ax)' + cos(bx)(bx)' = a(ln3)3ax + bcos(bx)
y" = a(ln3)(ln3)3ax(ax)' + b(-sin(bx))(bx)' = (aln3)23ax - b2sin(bx)