Reeeeeb W.
asked 12/14/23Equation of the tangent
Determine the equation of the tangent to the curve: cos (x y) = ye^x -pi/2
at the point (x; y) = (0,pi/2) you will need to use implicit differentiation.
1 Expert Answer
Mark M. answered 12/14/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
(0, π/2) is not a solution of cos(xy) = yex - π/2, but is a solution of the equation cos(x+y) = yex - π/2.
cos(x+y) = yex - π/2
-sin(x + y)(1 + dy/dx) = (dy/dx)ex + exy
At the point (0, π/2), we have -sin(π/2)(1 + dy/dx) = (dy/dx)(1) + π/2
-1 - dy/dx = dy/dx + π/2
2(dy/dx) = -1 - π/2
dy/dx = -1/2 - π/4
Tangent line: y - π/2 = (-1/2 - π/4)(x - 0)
Still looking for help? Get the right answer, fast.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Luke J.
is the equation cos(x + y) = y*e^(x)-pi/2?12/14/23