
Yefim S. answered 12/11/23
Math Tutor with Experience
N = N0bt; 0.776N0 = N0b300; b300 = 0.776; b= (0.776)1/300.
(a) 0.5N0 = N0(0.776)t/300; t/300 = ln0.5/ln0.776; t = 300ln0.5/ln0.776 = 820 days(half-life time)
(b) 1/3N0 = N0(0.776)t/300; t = 300ln(1/3)/ln0.776 = 1300 days