
Yefim S. answered 12/10/23
Math Tutor with Experience
Surface Area S = 2π∫0π/6rcosθ√((r2 + (dr/dθ)2)dθ = 2π∫0π/25sin3θcosθ√25sin23θ + 225cos23θdθ = 90.1556
Gabrielle M.
asked 12/09/23Find the Surface Area of Rotating the following section of the graph around the given axis. Round answer to two decimal places.
Take the curve on the interval
Rotated around the polar axis
The Surface Area is
Yefim S. answered 12/10/23
Math Tutor with Experience
Surface Area S = 2π∫0π/6rcosθ√((r2 + (dr/dθ)2)dθ = 2π∫0π/25sin3θcosθ√25sin23θ + 225cos23θdθ = 90.1556
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