
Yefim S. answered 02/01/24
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Area of inner loop A = 2·1/2∫0π(3 - 4cosθ)2dθ = ∫0π(9 - 24cosθ + 16cos2θ)dθ = (9θ - 24sinθ + 8θ + 4sin2θ)0π = 17π
Gabrielle M.
asked 12/09/23Find the area of the inner loop of the graph. Round answer to two decimal places.
The area of the inner loop is
Yefim S. answered 02/01/24
Math Tutor with Experience
Area of inner loop A = 2·1/2∫0π(3 - 4cosθ)2dθ = ∫0π(9 - 24cosθ + 16cos2θ)dθ = (9θ - 24sinθ + 8θ + 4sin2θ)0π = 17π
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