Mark M. answered 12/10/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
r = 5sin(3θ)
When θ = 0, r = 0
When θ = π/6, r = 5
When θ = π/3, r = 0
You can see the graph on Wolfram Alpha, for example.
The graph has 3 loops, each of which has the same area.
One loop is traced out as θ varies from 0 to π/3.
Area of loop = (1/2)∫ r2dθ = (25/2)∫(0 to π/3) sin2(3θ)dθ = (25/4)∫(0 to π/3) (1 - cos(6θ))dθ
= (25/4) [ θ - (1/6)sin(6θ) ](0 to π/3) = (25/4) [ (π/3 - 0) - (0) ] = 25π/12