Raymond B. answered 12/05/23
Math, microeconomics or criminal justice
1 pm ship A is 5 km west of ship B
ship A is traveling west at 20 km/hr
ship B is traveling north at 30 km/hr
how is the distance between them changing at 3pm?
it helps to draw a rough sketch
in 2 hours A is 45 miles west of B's original location
in 2 hours B is 60 miles north of B's original location
contruct a right triangle with legs 45 and 60, calculate the hypotenuse= sqr(45^2+60^2)=75 km
h^2 = n^2 + w^2
take the derivative
2hh' = 2nn' + 2ww'
divide by 2
hh' = nn' +ww'
75h' = 60(30)+45(20)
h' = (1800+900)/75
h'= 2700/75 = 108/3= 36 km/hr = rate of change of distance between the two ships