Mark M. answered 11/30/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
C(x) = 0.6x2 + 21x + 1215
Marginal cost = C'(x) = 1.2x + 21
Average cost = A(x) = C(x) / x = 0.6x + 21 + 1215 / x
A'(x) = 0.6 - 1215 / x2 = (0.6x2 - 1215) / x2 = 0
0.6x2 = 1215
x2 = 2025 So, x = 45
Minimum average cost when x = 45
At x = 45, marginal cost = C'(45) = 1.2(45) + 21 = 75
Minimum average cost = A(45) = 0.6(45) + 21 + 1215/45 = 75