Mark M. answered 11/29/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
A = 68000ert = amount after t years
68000e5r = 92000
e5r = 1.35294
5r = ln(1.35294) = 0.30228
r = 0.060456 ≈ 6.05%
Opal M.
asked 11/29/23If an investment compounded continuously grows from $68,000 to $92,000 in five years, what is the interest rate to the nearest hundredth of a percent?
Mark M. answered 11/29/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
A = 68000ert = amount after t years
68000e5r = 92000
e5r = 1.35294
5r = ln(1.35294) = 0.30228
r = 0.060456 ≈ 6.05%
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