Mark M. answered 11/20/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let f(x) = x4/5
Since 2434/5 = 34 = 81, use the Taylor Series for f centered at 243:
81 + f'(243)(x - 243) + [f"(243) / 2!](x-243)2 + [f'''(243)} / 3!](x - 243)3 + ...
2454/5 = f(245) = 81 + (4/5)(1/3)(2) - (4/25)(243)-6/5(1/2)(2)2 + (24/125)(243)-11/5(1/6)(2)3 + ...
On a calculator, 2454/5 ≈ 81.53289581
Using the Taylor Polynomial of degree 2 for the Taylor Series defined above (I.e., using the sum of the first 3 terms of the Taylor Series), we get 2454/5 ≈ 81.53289438.