
Yefim S. answered 11/17/23
Math Tutor with Experience
e3x - x - 8 = 0; x0 = 0.5; f'(x) = 3e3x - 1; xn+1 = xn - f(xn)/f'(xn) = xn - (e3x - x - 80.822)/(3e3x - 1);
x1 = 0.822884;
x2 = 0.736200
x3 = 0722259
x4 = 0.721948
x5 = 0.721948
Wesley W.
asked 11/17/23Use Newton's method to approximate the indicated solution of the equation correct to six decimal places.
the positive solution of e3x = x + 8
Yefim S. answered 11/17/23
Math Tutor with Experience
e3x - x - 8 = 0; x0 = 0.5; f'(x) = 3e3x - 1; xn+1 = xn - f(xn)/f'(xn) = xn - (e3x - x - 80.822)/(3e3x - 1);
x1 = 0.822884;
x2 = 0.736200
x3 = 0722259
x4 = 0.721948
x5 = 0.721948
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