
William W. answered 11/15/23
Experienced Tutor and Retired Engineer
Make a sketch:
Since we are being asked "to get there quickest", that means we want to minimize time. So we need to develop a function for the time it takes, and minimize it, i.e., take the derivative, set it equal to zero, and find the minimum time.
time = distance/rate
The distance to row is found using the Pythagorean Theorem:
drow = √(32 + x2) = √(x2 + 9)
The rate for rowing is 2 so the time spent rowing is √(x2 + 9)/2 or (1/2)(x2 + 9)1/2
The distance to walk is 8 - x.
The rate for walking is 5 so the time spent walking is (8 - x)/5 = 8/5 - (1/5)x
So the function for time is:
t(x) = (1/2)(x2 + 9)1/2 + 8/5 - (1/5)x
Take the derivative:
t'(x) = (1/4)(x2 + 9)-1/2(2x) - 1/5
Then set it equal to zero and solve:
(1/4)(x2 + 9)-1/2(2x) - 1/5 = 0
(1/4)(x2 + 9)-1/2(2x) = 1/5
1/(x2 + 9)1/2 = 2/(5x)
cross multiply to get:
2(x2 + 9)1/2 = 5x
[(x2 + 9)1/2]2 = (2.5x)2
x2 + 9 = 6.25x2
9 = 5.25x2
x2 = 9/5.25
x = 1.309 miles