
Emery J.
asked 11/15/23How derivatives Affect the shape of a graph
4. T/F (with justification) If a function f(x) on the interval (−1,1) is twice differentiable and f′′(c) = 0 for some c in (−1,1) then f(x) has an inflection point at x = c.
2 Answers By Expert Tutors

William W. answered 11/16/23
Experienced Tutor and Retired Engineer
f " = 0 only tells you POTENTIAL points of inflection. You must always check to see if there is a change in concavity at that point. If concavity changes, then it's a POI. If not, it is not a POI.
Eric W. answered 11/15/23
Aerospace Engineer With A Passion For Math and Science
False
the function is twice differentiable on the interval (-1,1) so the function is smooth and continuous. This is an important distinction because if you have some function with breaks in it or sharp points then the following is not necessarily true.
We know that f''(c) = 0 would be a critical point however for it to be an inflection point the sign of f''(x) would have to change value as it crosses c and this is not always the case.
Take the function f(x) = x4
f''(x) = 12x2
f''(0) = 0 however f''(x) ≥ 0 over the region (-1,1) so this function would not have an inflection point at x=0 and the concavity remains positive over (-1,1).
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Doug C.
Try the function f(x) = x^4. desmos.com/calculator/poud4ly6fr11/15/23