Use Bayes Theorem.
The probability of drawing a white ball from Urn 1 is 1/5. The probability of drawing a white ball from Urn 2 is 4/5. So this
(1/5) / [ (1/5) + (4/5) ] = 1 / [ 1 + 4 ]
= 1/5 that the white ball came from Urn 1.
Joanna C.
asked 11/13/23One of two urns is chosen at random with one as likely to be chosen as the other. Then a ball is withdrawn from the chosen urn. Urn 1 contains 1 white and 4 red balls, and urn 2 has 4 white and 1 red ball. If a white ball is drawn, what is the probability that it came from urn 2? Type as a fraction simplified the answer.
Use Bayes Theorem.
The probability of drawing a white ball from Urn 1 is 1/5. The probability of drawing a white ball from Urn 2 is 4/5. So this
(1/5) / [ (1/5) + (4/5) ] = 1 / [ 1 + 4 ]
= 1/5 that the white ball came from Urn 1.
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