Mark M. answered 11/10/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
i4 / n5 + i / n2 = (i4 / n4 + i / n)(1/n) = [ (i / n)4 + (i / n)] (1/n) = f(xi)Δx
The value of the limit is ∫ (0 to 1) [x4 + x]dx.
Lucas S.
asked 11/10/23limn→∞∑ni=1(i4/n5+i/n2)
I got Δx=1/n and xi=i/n but I'm not sure how else to proceed by the Riemann sum method.
Mark M. answered 11/10/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
i4 / n5 + i / n2 = (i4 / n4 + i / n)(1/n) = [ (i / n)4 + (i / n)] (1/n) = f(xi)Δx
The value of the limit is ∫ (0 to 1) [x4 + x]dx.
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