
Yefim S. answered 11/09/23
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∑k=11∞(4k - 10/3k + 20)k;
4k - 10/3k + 1 > 1; 4k - 10 > 3k + 20; k > 30
So lim k→∞ (4k - 10/3k + 20)k = ∞, gecause from k = 31 4k- 10/3k +m 20 > 1
So, this series diverges