
William W. answered 11/09/23
Experienced Tutor and Retired Engineer
You are maximizing area so write an equation for the area and then take the derivative. Then set the derivative equal to zero to solve for the local maximum.
Areacircular portion = (1/2)πr2
Arearectangular portion = L•W
So A = (1/2)πr2 + L•W
But, because "the diameter of the semicircle is equal to the width of the rectangle" then 2r = W
And because "the perimeter" is 20, then πr + 2L + W = 20
You can now substitute into the area equation to get the area as a function of a single variable.
Take the derivative, set it equal to zero, and solve.