
Yefim S. answered 11/08/23
Math Tutor with Experience
f'(x) = 7(x2- 25 - 2x2)/(x2 - 25)2 = -7(x2 + 25)/(x2 - 25)2; f'(x) = - 7[2x(x2 - 25) - 4x(x2 + 25)]/(x2 - 25)3 =
7(2x3 + 150x)/(x2 - 25)3; f''(x) = 0; x = 0
f) f''(x) > 0, (- 5, 0), (5, ∞) f(x) concave up
g)f''(x) < 0; (- ∞, - 5), (0, 5) f(x) concave down