
Yefim S. answered 11/08/23
Math Tutor with Experience
x2z = 50; Cost C = 8x2 + 28xz; z = 50/x2; C = 8x2 + 1400/x; C' = 16x - 1400/x2 = 0; 16x3 = 1400;p x3 = 175/2;
x = (175/2)1/3 = 4.44 ft; z = 50/(175/2)2/3 = 2.54 ft
This is minimum cost because C'' = 16 + + 2800/x3 = 16 + 2800/(175/2) = 48 > 0