What is the equation of the line?

Question

Slope = 4; containing the point (7, -9)

Answer 1

Hello, thank you for taking the time to post your question!

The underlying equation that you want to use here is the point-slope form of a linear equation:

y−y1​=m(x−x1​)

For this set of values, we have a slope m=4 and a point (x1​,y1​)=(7,−9).

Plugging these values into the point-slope equation gives you: y−(−9)=4(x−7)

Solving that algebraically for the value of “y” to put it into the slope-intercept form (y=mx+b) yields: y+9=4x−28

y=4x−28−9

y=4x−37

I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

equation of line in slope intercept form : y=mx+b

where

m=slope

b=y-intercept

 

line containing point(7,-9)

 

so y= mx+b

     -9=4(7) +b

     -9=28+b

      -9-28=b

       -37 = b

 

equation of line in slope intercept form:

 

y= mx+b

 

y=4x-37