Inactive Tutor answered 11/02/23
Tutor
New to Wyzant
lim x→∞ [√(x2 + 3x + 12) - x] = lim x→∞ (3x + 12)/[√(x2 + 3x + 12) + x] = lim x→∞ (3 + 12/x)/[√1 + 3/x + 12/x2) + 1] = (3 + 0)/[√(1 + 0 + 0) + 1] = 3/2
June K.
asked 11/02/23The limit
lim x approaches infinity sqrt ( x^2+3x+12 ) - x
Inactive Tutor answered 11/02/23
lim x→∞ [√(x2 + 3x + 12) - x] = lim x→∞ (3x + 12)/[√(x2 + 3x + 12) + x] = lim x→∞ (3 + 12/x)/[√1 + 3/x + 12/x2) + 1] = (3 + 0)/[√(1 + 0 + 0) + 1] = 3/2
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