Mark M. answered 11/02/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = ex / (4 + ex)
f'(x) = [ex(4 + ex) - ex(0 + ex)] / (4 + ex)2 = 4ex / (4 + ex)2 > 0 for all x.
f is increasing on (-∞, ∞)
f is never decreasing
f has no local extrema
f"(x) = [4ex(4 + ex)2 - 2(4 + ex)(ex)(4ex)] / (4 + ex)4 = [4ex(4 + ex)(4 + ex - 2ex)] / (4 + ex)4
= [4ex(4 - ex)] / (4 + ex)3 = 0 when ex = 4. So x = ln4.
When x < ln4, f"(x) > 0. So, f is concave up
When x > ln4, f"(x) < 0. So, f is concave down
Inflection point: (ln4, f(ln4)) = (ln4, 1/2)