Raymond B. answered 03/12/23
Math, microeconomics or criminal justice
s(x) = (x-1)^2/(x^2(x-3))
x = any number except 0 or 3, as they make the denominator = 0 which is not allowed as it makes s(x) undefined
x=0 and x =3 are vertical asymptotes
range = all numbers
even though it seemingly is except s(x) = 0 which is a horizontal asymptote
0 is the ratio of the highest degreed term in the numerator over the highest degreed term in the denominator = x^2/ x^3 = 1/x which appraches zero as x approaches infinity or negative infinity
but
s(x) = 0= (x-1)^2/(x^2(x-3))
x^2 -2x +1 = 0
x= 1
even though to the right and left, y=0 is an asymptote
it may helpt to graph the function