William C. answered 10/23/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
I = 2∫dx ⁄ √(x+5) from –5 to 5 Let u = √(x+5), x+5 = u², dx = 2udu, dx ⁄ √(x+5) = 2udu/u = 2du
So I = 2∫dx ⁄ √(x+5) from –5 to 5 = 2∫2du from √(–5+5) to √(5+5)
I = 4∫du from 0 to √(10) = 4√(10) – 0
Answer
I = 4√(10)