Mark M. answered 10/18/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
V = (4/3)πr3
dV/dt = 4πr2(dr/dt) = 4π(14)2(-0.1)
Hey L.
asked 10/18/23A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.1 cm/min. At what rate is the volume of the snowball changing when the radius is 14 cm. Round your answer to the nearest tenth.
_______ cm3/min
Hint: The volume of a sphere of radius r is V = 4/3πr3
Mark M. answered 10/18/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
V = (4/3)πr3
dV/dt = 4πr2(dr/dt) = 4π(14)2(-0.1)
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