Mark M. answered 10/19/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let x = base, y = height, and z = hypotenuse
z2 = x2 + y2 When x = 10 and y = 16, z = √(100 + 256) = √356 = 2√89
2z(dz/dt) = 2x(dx/dt) + 2y(dy/dt)
dz/dt = [x(dx/dt) + y(dy/dt)] / z = [40 + 48] / (2√89) = 44 / √89