If g(x)=5+x+2e^x, find g^-1(7)

Yefim S. answered • 10/17/23

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g(x) = 7; 5 + x + 2e^x = 7; x + 2e^x = 2; x = 0. g^-1(7) = 0; g'(x) = 1 + 2e^x; g'(0) = 3

(g^-1)^'(7) = 1/g'(0) = 1/3

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