
Bradford T. answered 10/07/23
Retired Engineer / Upper level math instructor
a) f(x)=√(x2-9arcsec(x))
First let y=9arcsec(x)
ln(y) = arcsec(x)ln(9)
y'/y = ln(9)/(x2√(1-1/x2))
y' = yln(9)/(x2√(1-1/x2)) = 9arcsec(x)ln(9)/(x2√(1-1/x2))
f(x) = √(x2-y)
f'(x) = (1/(2√(x2-y)))(2x-y') = (1/(2√(x2-y)))(2x-9arcsec(x)ln(9)/(x2√(1-1/x2)))
b) y = 12xsin-1(x)+√(9-x2)
y = 12x/(x2√(1-1/x2))+12sin-1(x) - x/√(9-x2)