William C. answered 10/06/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
a) Find (f–1)'(a).
f(x) = x3 + 3sinx + 2cosx, a = 2
Set f(x) = 2 and solve for x
x3 + 3sinx + 2cosx = 2 when x = 0
Calculate f'(0)
f'(x) = 3x2 + 3cosx – 2sinx
f'(0) = 3
(f–1)'(3) = 1/f'(0) = 1/3
b) ln(1+x2) – ln(1+x) = ln[((1 + x2)/(1 + x)] → ln x as x →∞ and ln x→∞ as x →∞
So [ln(1+x2) – ln(1+x)] →∞ as x →∞