Mark M. answered 10/03/23
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(6+h) - f(6) = ah + bh2 + ch3
[f(6+h) - f(6)] / h = a + bh + ch2
Taking the limit as h approaches 0 of both sides, we have f'(6) = a + b(0) + c(0)2 = a