William C. answered 10/03/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
(a) What type of discontinuity does the function 𝑔(𝑥) = 1/(𝑒1/x – 1) have at 𝑥 = 0
As x→0, the left-hand side limit (-1) and right-hand side limit (0) are different. So it's a jump discontinuity.
(b) For which value of 𝑐 will the function 𝑓(𝑥) = (1/(𝑒1/x − 1) + 𝑐)2 have a limit at 𝑥=0?
For c = 0 there is a jump discontinuity
where the left-hand side limit = 0 and where the right-hand side limit = 1
When c = 1/2, the left-hand side and right-hand side limits both equal 1/4
So 𝑓(𝑥) has a limit when c = 1/2
(c) Using the value found in part (b), how would you define 𝑓(𝑥) at 𝑥 = 0 so that 𝑓 becomes continuous at 𝑥=0?
You define 𝑓(𝑥) = 1/4 at 𝑥 = 0