
Yefim S. answered 10/01/23
Math Tutor with Experience
v = 1/3πr2h = 1/12πh3; dv/dt = 1/4πh2dh/dt; dh/dt = 4dv/dt/(πh2) = 4·40ft3/min/(π·400ft2) = 0.1273 ft/min
Landon B.
asked 10/01/23Gravel is being dumped from a conveyor belt at a rate of 40 cubic feet per minute. It forms a pile in the shape of a right circular cone whose base diameter and height are always the same. How fast is the height of the pile increasing when the pile is 20 feet high? Recall that the volume of a right circular cone with height h and radius of the base r is given by V=(1/3)πr2ℎ.
Yefim S. answered 10/01/23
Math Tutor with Experience
v = 1/3πr2h = 1/12πh3; dv/dt = 1/4πh2dh/dt; dh/dt = 4dv/dt/(πh2) = 4·40ft3/min/(π·400ft2) = 0.1273 ft/min
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.