Mark M. answered 09/27/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
h(x) = 2x + f(x)g(x)
h'(x) = 2 + f'(x)g(x) + g'(x)f(x)
So, h'(3) = 2 + f'(3)g(3) + g'(3)f(3) = 2 + (8)(-4) + (2)(-2) = -34
Josephine J.
asked 09/27/23x = 1, 2, 3, 4
f(x) = 3, 5, −2, 0
g(x) = 2, 3, −4, 6
f′(x) = −1, 7, 8, −3
g′(x) = 4, 1, 2, 9
Note: The list of numbers is supposed to be a table. I tried to line everything up.
Mark M. answered 09/27/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
h(x) = 2x + f(x)g(x)
h'(x) = 2 + f'(x)g(x) + g'(x)f(x)
So, h'(3) = 2 + f'(3)g(3) + g'(3)f(3) = 2 + (8)(-4) + (2)(-2) = -34
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