
Reginald J. answered 09/22/23
10+ Year Experienced Calculus Whiz (1st session free)
Hi Pauline,
You want to swap x and y initially: x=(y-2)/(1+8y)
Now, solve for y. Notice that there are two of them, however. You want to multiply the denominator by x and set it equal to the numerator: x(1+8y)=y-2.
Distribute: x+8xy=y-2.
Subtract y from both sides and subtract x from both sides: 8xy-y=-x-2.
Now you can factor out a y so that it's singular in the equation: y(8x-1)=-x-2
Divide both sides by "8x-1": y^-1= (-x-2)/(8x-1) or y-1=(x+2)/(1-8x).
The original function is one-to-one so you don't have to worry about domain restrictions.
I hope this helps!