Mark M. answered 09/18/23
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
sin(θ/2) = ±√ [(1 - cosθ) / 2 ]
So, sin2(θ/2) = (1 - cosθ) / 2
sin2(7π/8) = sin2[ (7π/4) / 2 ] = (1 - cos(7π/4)) / 2 = (1 - √2/2) / 2 = (2 - √2) / 4