Pauline Y.

asked • 09/16/23

Here is a table of values for the function 𝑓(𝑥)=ln(𝑥−1)/2𝑥−4.

Here is a table of values for the function 𝑓(𝑥)=ln(𝑥−1)/2𝑥−4.

𝑥 𝑓(𝑥)
1.9 0.526803
1.99 0.502517
1.999 0.50025
1.9999 0.500025
2.0001 0.49975
2.001 0.49975
2.01 0.497517
2.1 0,476551


Based on the table, it seems like lim𝑥→2𝑓(𝑥)=?


0

1/2

does not exist.

2

21/2


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