Gas law homework question.

Question

The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV = nRT, where n is the number of moles of the gas and R = 0.0821 is the gas constant. Suppose that, at a certain instant, P = 7.0 atm and is increasing at a rate of 0.13 atm/min and V = 13 L and is decreasing at a rate of 0.17 L/min. Find the rate of change of T with respect to time at that instant if n = 10 mol. (Round your answer to four decimal places.)

1. I've gotten the answer 0.6083 K/min and it's wrong. Did I do something wrong? What is the answer then?

Answer 1

Answer 2

PV = nRT

P(dV/dt) + V(dP/dt) = nR(dT/dt)

(7.0)(-0.17) + (13)(0.13) = (10)(0.0821)(dT/dt)

dT/dt = 0.6090