
Bradford T. answered 09/09/23
Retired Engineer / Upper level math instructor
For vectors to be perpendicular, their dot products must be zero.
i)
u•w = ux-uz = 0
v•w = vx-vz =0
ii)
u•v = uxvx+uyvy+uzvz = 0
2uzvz + uyvy = 0 --> 2uzvz= -uyvy
Let uz=1, vz=1, uy=-2, vy=1
uxvx -2 +1 = 0 --> uxvx=1
Let ux= vx= 1
u = (1,-2,1) v = (1,1, 1)
Checking:
u • v = 1-2+1 = 0
u • w = 1+0-1 = 0
v • w = 1 +0 -1 = 0

Bradford T.
From i) ux=uz and vx=vz. Then substitute for ux and uz in the first line of ii) which give 2uzvz09/10/23
Clinton E.
Thank you so much for your response. Please how did you arrive at 2uzvz + uyvy?09/10/23