Bradford T. answered • 09/02/23
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g(x) = ∫g'(x) dx = 4x3-9x+C
g(-7) = -1309 + C = 40
C = 1349
g(x) = 4x3-9x+1349
Alecia S.
asked • 09/02/23calculus help..
Given that g'(x)=12x2-9 and g(-7)=40, find g(x)
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