calculus for life science

Question

The height of a ball t seconds after it is thrown from the top of a building is given by

H(t)=−16t2+47t+122. Find its​ height, velocity, and acceleration

3 seconds after it is thrown from the building.

The​ ball's height after 3 seconds is

enter your response here

ft.

The​ ball's velocity after 3 seconds is

enter your response here

ftsec.

The​ ball's acceleration after 3 seconds is

enter your response here

ftsec2.

Answer 1

h(t) =-16t^2 +47t + 122

in 3 seconds

height = h(3) = -16(9) +47(3) +122 = -144 +141 +122 = 125 feet high

velocity = h'= -32(3) +47 = -96 +47 =-49 feet per second

acceleration = h"(3) = -32 feet per second per second