Inactive Tutor answered 08/16/23
For Rolle's Theorem to apply, f(a) must equal f(b) on the interval [a, b] and the function must be differentiable and continuous on (a, b).
For [-3, 2], does f(-3) = f(2)? If not, Rolle's Theorem is not applicable,
Constance V.
asked 08/16/23Please show as much work as possible. Thank you!
Determine if Rolle’s Theorem can be applied. If Rolle’s Theorem can be applied, find all values of c in the interval such that f'(c) = 0, f (x) = (x + 3)(x + 2) 2 closed interval [-3, 2]
Inactive Tutor answered 08/16/23
For Rolle's Theorem to apply, f(a) must equal f(b) on the interval [a, b] and the function must be differentiable and continuous on (a, b).
For [-3, 2], does f(-3) = f(2)? If not, Rolle's Theorem is not applicable,
Inactive Tutor answered 08/16/23
f(x) = (x+3)(x+2)^2
f(-3) =(-3+3)(-3+2)^2 = 0(1) = 0
f(2) = (2+3)(2+2)^2 = 5(16) = 80
f'(x) = (x+3)(2) + (x+2) = 2x+6+x+2 = 3x+8
f'(c) = 3c+ 8 = (80-0)/(2+3) = 16
3c+8 =16
c= (16-8)/3
c = 8/3
Rolle's Theorem doesn't apply, but the Mean Value Theorem does apply giving
c=8/3
Rolles' Theorem is just the Mean Value Theorem with one little added restriction
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